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Geometric Series Calculator

Sum of geometric series, finite and infinite.

1200
Enter values above — results appear instantly as you type.
AI Insight: Geometric series have a closed-form sum: a(1-r^n)/(1-r) for finite series, a/(1-r) for infinite if |r|<1. The infinite case explains how Zeno's paradox resolves — the infinite sum of decreasing distances converges to a finite total.
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Written with AI assistance and checked by automated validation · Last updated: August 2026 · How we build and check this · Methodology
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Formula

S = a(1-r^n)/(1-r)

Example

a=2, r=0.5, n=10 → Sum ≈ 3.998.

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Understanding the Geometric Series Calculator

A geometric series calculator sums a sequence where each term multiplies the previous one by a fixed ratio, and reports whether the infinite sum converges. That convergence condition is the interesting part: an infinite sum of infinitely many positive terms can be finite.

How it actually works

Enter the first term, common ratio, and number of terms. The calculator sums the finite series and, where the ratio is under one in absolute value, gives the infinite sum. Starting at 10 with a ratio of 0.5 gives 19.98 over ten terms against an infinite sum of exactly 20.

Convergence by ratio
Ratio rInfinite behaviour
|r| < 1Converges to a/(1−r)
r = 1Diverges, sum is a·n
r = −1Oscillates, no limit
|r| > 1Diverges

The deeper context most people miss

Convergence when the ratio is under one in absolute value is what resolves Zeno's dichotomy paradox: crossing a room requires infinitely many halving steps, and those steps sum to a finite distance covered in finite time, so the infinity of steps is not an obstacle.

Why the sum formula works

The derivation is short and worth knowing. Write the sum S of n terms, multiply the whole thing by the ratio r, and subtract: almost every term cancels, leaving S minus rS equal to the first term minus the first term times r to the n. Solving gives the standard formula. For the infinite case, when the absolute value of r is under one, r to the n approaches zero as n grows, so the numerator simplifies and the sum becomes the first term over one minus r. That is the entire argument, and it makes the convergence condition transparent rather than arbitrary: the sum converges precisely when the terms shrink geometrically toward zero fast enough for the tail to vanish. The formula also handles negative ratios, where terms alternate in sign and the series still converges if the magnitude shrinks, and the case r equals one requires separate treatment since the formula divides by zero, which is why the calculator tests for it. This telescoping trick generalises: multiplying a sum by something and subtracting to induce cancellation is a standard technique that appears in generating functions, in solving recurrences, and in summing many other series, and recognising it as a method rather than a one-off makes several apparently different results look like the same idea.

A worked example: why 0.999 recurring equals one

A first term of 10 with ratio 0.5 sums to exactly 20 over infinitely many terms, and the same reasoning settles a question people argue about endlessly. The decimal 0.999 recurring is the geometric series with first term 0.9 and ratio 0.1, which sums to 0.9 divided by 0.9, exactly one. This is not an approximation and the two are not merely very close; they are the same number written two ways, in the same sense that one half and two quarters are. The resistance to this comes from treating an infinite decimal as a process that never quite finishes rather than as a number defined by the limit of its partial sums, which is what the definition actually says. Several other arguments reach the same place: one third is 0.333 recurring, so multiplying by three gives one on the left and 0.999 recurring on the right; and subtracting 0.999 recurring from one gives a difference smaller than any positive number, which in the real numbers means the difference is zero, since the reals contain no infinitesimals. Systems that do contain infinitesimals exist, including the hyperreals, and in those the question becomes more subtle, but standard real analysis is unambiguous.

Deciding where geometric series appear

They describe anything with a constant proportional change per step, which covers a great deal of finance. Compound interest produces a geometric sequence of balances. The present value of a perpetuity, a payment stream continuing indefinitely, is an infinite geometric series and sums to the payment divided by the discount rate, which is why perpetuity valuation has such a simple formula. Annuity and loan amortisation formulas are finite geometric series, which is why the standard mortgage payment formula has the shape it does rather than being arbitrary. Depreciation by a fixed percentage produces a geometric sequence. In economics, the multiplier effect is a geometric series, where each round of spending is a fixed fraction of the previous. In physics, a bouncing ball rebounding to a fixed fraction of its height has both total distance and total time as geometric series, and the total time being finite is why the ball stops bouncing despite infinitely many bounces in principle. Radioactive decay measured at fixed intervals is geometric. In computing, algorithm analysis produces geometric series when work halves at each level of recursion, and summing them is what gives the linear rather than logarithmic total in several divide-and-conquer analyses.

When the sum formula misleads: divergence and rearrangement

Applying the formula outside its domain produces confident nonsense, and the historical record contains plenty of it. With ratio 2 and first term 1, the formula would give a sum of minus one for the series of powers of two, which is obviously wrong for a series of increasing positive terms, and the error is applying a result derived under an assumption that fails. Grandi's series, alternating one and minus one, has partial sums oscillating between one and zero and no limit, and the formula would suggest one half, which is a value that can be assigned by certain summation methods including Cesàro summation but is not the sum in the ordinary sense. These assigned values are not merely fanciful: analytic continuation gives the famous result associating the sum of all positive integers with minus one twelfth, which appears in physics through zeta regularisation and is routinely misreported as though the ordinary sum were negative. The distinction between an ordinary sum and a regularised value assigned by a consistent extension is the whole content there. For conditionally convergent series, the Riemann rearrangement theorem shows the order of addition changes the sum arbitrarily, so infinite sums do not obey commutativity in the way finite ones do, which is one of the sharper reminders that infinity requires care rather than intuition.

Variations: related series and convergence tests

Arithmetic series add a constant and always diverge when infinite. The harmonic series sums reciprocals of integers and diverges despite its terms shrinking to zero, which is the standard counterexample to the intuition that shrinking terms guarantee convergence. The p-series generalises it, converging when the exponent exceeds one, so the sum of reciprocal squares converges while the sum of reciprocals does not, and the reciprocal squares sum to π squared over six, which was the Basel problem solved by Euler. Power series generalise geometric series by allowing coefficients, and Taylor series express functions as power series, with the radius of convergence playing the role the ratio condition plays here. The ratio and root tests determine convergence generally and both reduce to the geometric condition in the simple case. Telescoping series collapse by cancellation. Alternating series converge under weaker conditions than absolute convergence requires. For practical computation, a convergent geometric series is easy to evaluate to any precision since the tail is bounded by the next term over one minus the ratio, giving a rigorous error bound rather than an estimate.

Working with geometric series

Check the ratio before applying the infinite sum formula, since it requires the absolute value to be under one and applying it outside that range produces meaningless results. Derive the formula by multiplying by the ratio and subtracting, which makes the convergence condition transparent and is a technique that generalises. Recognise that 0.999 recurring equals one exactly, being the geometric series with first term 0.9 and ratio 0.1, rather than merely approaching it. Handle the ratio equals one case separately, since the formula divides by zero and the sum is simply the first term times the count. Recognise perpetuity, annuity, and loan amortisation formulas as geometric series, which makes their structure comprehensible rather than arbitrary. Note that the harmonic series diverges despite shrinking terms, so shrinking alone does not guarantee convergence. Treat regularised values including the minus one twelfth result as assignments by a consistent extension rather than as ordinary sums. And bound the truncation error by the next term over one minus the ratio, which gives a rigorous rather than estimated error.

What people get wrong

  • Applying the infinite sum formula when the ratio's absolute value is at least one, which produces results such as a negative sum for a series of increasing positive terms.
  • Treating 0.999 recurring as merely close to one, when it is the same number, being a geometric series that sums to exactly one by the definition of an infinite decimal.
  • Assuming shrinking terms guarantee convergence, when the harmonic series has terms approaching zero and still diverges without bound.
  • Reporting regularised values such as the sum of all integers being minus one twelfth as ordinary sums, when they are assignments from analytic continuation rather than limits of partial sums.

Where the math comes from

The sum of n terms is a(1 − rⁿ)/(1 − r) for r ≠ 1, derived by multiplying the sum by r and subtracting so that all but two terms cancel. When |r| < 1, rⁿ approaches zero and the infinite sum converges to a/(1 − r). For r = 1 the sum is simply a·n, and for |r| ≥ 1 otherwise the infinite series diverges.

Questions and answers

Diameter vs radius?

Diameter is the distance across; radius is half of diameter. Different formulas use different ones - read carefully which the calculator expects.

How precise should I use pi?

For everyday problems, 3.14 is fine. For engineering, use pi = 3.14159 or more decimal places. The calculator typically uses many decimal places internally.

Why do my measurements not match the formula?

Real objects have manufacturing tolerances, irregular shapes, and measurement error. Treat geometric calculations as ideals; physical reality often deviates 1-5%.

Surface area or volume?

Surface area is 2D (square units); volume is 3D (cubic units). Different formulas, different units. Mismatching is a common error.

How do I handle compound shapes?

Break into measurable simpler shapes (rectangles, triangles, circles), calculate each, and add. Subtract any holes or removed sections.

When does an infinite geometric series converge?

When the absolute value of the common ratio is under one, giving a sum of the first term over one minus the ratio. At ratio one it diverges linearly, at minus one it oscillates without a limit, and beyond one in magnitude it diverges.

Does 0.999 recurring really equal 1?

Exactly, yes. It's the geometric series with first term 0.9 and ratio 0.1, which sums to 0.9 divided by 0.9. They're the same number written two ways, and the resistance comes from treating an infinite decimal as an unfinished process.

How is the sum formula derived?

Multiply the sum by the ratio and subtract from the original. Nearly every term cancels, leaving a short expression to solve. The infinite case follows because the ratio raised to a growing power approaches zero when the ratio is under one.

Why does Zeno's paradox dissolve?

Because the infinitely many halving distances form a convergent geometric series summing to a finite total, covered in a finite time that is itself a convergent series. Infinitely many steps do not require infinite distance or duration.

What happens if the ratio is 1?

The formula divides by zero and doesn't apply. Every term equals the first, so the sum of n terms is simply the first term times n, and the infinite series diverges. Calculators must test for this case separately.

Do shrinking terms guarantee convergence?

No, and the harmonic series is the standard counterexample: its terms approach zero and the sum still grows without bound. Geometric shrinkage is fast enough; reciprocal shrinkage is not, which is why convergence tests exist.

Is the sum of all positive integers really minus one twelfth?

Not as an ordinary sum, which diverges. That value comes from analytic continuation of the zeta function, a consistent extension that assigns values to divergent series and appears in physics through regularisation. Reporting it as an ordinary sum is misleading.

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